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Cleveland, Utah : ウィキペディア英語版 | Cleveland, Utah
Cleveland is a town in Emery County, Utah. As of the 2000 census, the town population was 508. ==Geography== According to the United States Census Bureau, the town has a total area of 0.9 square mile (2.3 km²), all land. Cleveland is located in a swale of land between the mountains and the desert. It embraces about and is northeast of Huntington, southwest of Price, and northeast of Castle Dale.
抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)』 ■ウィキペディアで「Cleveland, Utah」の詳細全文を読む
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